1ere equation : -2(2y-4)=6y-(-3+y) 2eme equation : 4y-2+(5y-1)=-3(7-y)
Mathématiques
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Question
1ere equation : -2(2y-4)=6y-(-3+y)
2eme equation : 4y-2+(5y-1)=-3(7-y)
1 Réponse
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1. Réponse anton95
-2(2y-4)=6y-(-3+y)
-4y+8=6y+3-y
8-3=5y+4y
5=9y
5/9=y
4y-2+(5y-1)=-3(7-y)
4y-10y+2=-21+3y
-6y+2=3y-21
23=9y
23/9=y